How to Find Area of Similar Figures: Formula, Examples, Notes & Worksheet

Area of similar figures formula with similar triangles and scale factor

Introduction

Similar figures are geometric figures that have the same shape but not necessarily the same size. Their corresponding angles are equal, and their corresponding sides are proportional.

One important property of similar figures is the relationship between their side lengths and areas. If the lengths of corresponding sides of two similar figures are known, we can use the scale factor to find the area of one figure from the area of the other.

The most important rule to remember is:

The ratio of the areas of two similar figures is equal to the square of the ratio of their corresponding side lengths.

In this article, you will learn:

  • What similar figures are
  • How corresponding sides are related
  • How to find the scale factor
  • The area of similar figures formula
  • How to find an unknown area
  • How to solve problems involving triangles, rectangles, and other similar figures
  • Common mistakes students make
  • Practice questions and a worksheet

What Are Similar Figures?

Two figures are called similar figures if they have the same shape but may have different sizes.

For two similar figures:

  1. Their corresponding angles are equal.
  2. Their corresponding sides are proportional.
  3. They have the same shape.
  4. Their side lengths may be different.
  5. Their areas are related by the square of the scale factor.

For example, two squares with side lengths 4 cm and 8 cm are similar because both are squares.

The ratio of their corresponding sides is:84=2\frac{8}{4}=2

Therefore, the larger square is an enlargement of the smaller square by a scale factor of 2.

However, their areas are not in the ratio 2:12:1. Their areas are in the ratio:22:12=4:12^2:1^2=4:1

This is the key idea behind finding the area of similar figures.

How Are Similar Figures Related?

Suppose two similar figures have corresponding side lengths aa and bb.

Their side-length ratio is:ab\frac{a}{b}

If the scale factor from the first figure to the second figure is kk, then:k=corresponding side of second figurecorresponding side of first figurek=\frac{\text{corresponding side of second figure}}{\text{corresponding side of first figure}}

The areas change by the square of the scale factor.

Therefore:A2A1=k2\frac{A_2}{A_1}=k^2

where:

  • A1A_1 = area of the first figure
  • A2A_2 = area of the second figure
  • kk = scale factor

Area of Similar Figures Formula

The main formula is:A2A1=(s2s1)2\boxed{\frac{A_2}{A_1}=\left(\frac{s_2}{s_1}\right)^2}

where:

  • A1A_1 and A2A_2 are the areas of two similar figures.
  • s1s_1 and s2s_2 are corresponding side lengths.

If the scale factor is kk, then:A2=k2A1\boxed{A_2=k^2A_1}

This is the most useful formula for problems involving the areas of similar figures.

Why Is the Scale Factor Squared?

Area is measured in two dimensions: length and width.

Suppose every length of a figure is multiplied by 3.

Then both dimensions are multiplied by 3:3×3=93\times3=9

Therefore, the area becomes 9 times as large.

Similarly:

  • Scale factor 22 → area factor 44
  • Scale factor 33 → area factor 99
  • Scale factor 44 → area factor 1616
  • Scale factor 55 → area factor 2525

So:Area factor=(scale factor)2\boxed{\text{Area factor}=(\text{scale factor})^2}

Diagram-Based Explanation

Imagine two similar triangles.

The smaller triangle has a corresponding side of 5 cm, while the larger triangle has the corresponding side of 10 cm.

A simple diagram can be described as:

Small triangle: corresponding side = 5 cm, area = A1A_1

Large triangle: corresponding side = 10 cm, area = A2A_2

The scale factor is:k=105=2k=\frac{10}{5}=2

Therefore:A2A1=22=4\frac{A_2}{A_1}=2^2=4

So the larger triangle has four times the area of the smaller triangle.

How to Find the Area of Similar Figures

Use the following steps.

Step 1: Identify corresponding sides

Make sure that the two side lengths you are comparing correspond to each other.

Step 2: Find the scale factor

Use:k=new corresponding sideoriginal corresponding sidek=\frac{\text{new corresponding side}}{\text{original corresponding side}}

Step 3: Square the scale factor

Calculate:k2k^2

Step 4: Apply the area formula

If the original area is known:A2=k2A1A_2=k^2A_1

Step 5: Include the correct square units

Area must be written in units such as:cm2,m2,mm2cm^2,\quad m^2,\quad mm^2

Worked Example 1: Finding the Larger Area

Two similar triangles have corresponding side lengths of 6 cm and 9 cm. The area of the smaller triangle is 24 cm224\text{ cm}^2. Find the area of the larger triangle.

Solution

First, find the scale factor:k=96=32k=\frac{9}{6}=\frac{3}{2}

Square the scale factor:k2=(32)2=94k^2=\left(\frac{3}{2}\right)^2=\frac{9}{4}

Now multiply the original area by 94\frac94:A2=24×94A_2=24\times\frac94A2=6×9A_2=6\times9A2=54A_2=54

Therefore:A2=54 cm2\boxed{A_2=54\text{ cm}^2}

Worked Example 2: Finding the Smaller Area

Two similar rectangles have corresponding lengths of 12 cm and 8 cm. The area of the larger rectangle is 90 cm290\text{ cm}^2. Find the area of the smaller rectangle.

Solution

The scale factor from the larger rectangle to the smaller rectangle is:k=812=23k=\frac{8}{12}=\frac23

Therefore:k2=(23)2=49k^2=\left(\frac23\right)^2=\frac49

The smaller area is:A2=90×49A_2=90\times\frac49A2=10×4A_2=10\times4A2=40A_2=40

Therefore:40 cm2\boxed{40\text{ cm}^2}

Worked Example 3: Finding the Area Ratio

Two similar figures have corresponding sides in the ratio:3:53:5

Find the ratio of their areas.

Solution

For similar figures, area ratio is the square of the side ratio.

Therefore:Area ratio=32:52\text{Area ratio}=3^2:5^2=9:25=9:25

Therefore:9:25\boxed{9:25}

The figure with corresponding side 5 units has an area that is 259\frac{25}{9} times the area of the figure with corresponding side 3 units.

Worked Example 4: Finding an Unknown Area

Two similar figures have corresponding sides of 7 cm and 14 cm. The area of the smaller figure is 18 cm218\text{ cm}^2. Find the area of the larger figure.

Solution

Scale factor:k=147=2k=\frac{14}{7}=2

Area factor:k2=22=4k^2=2^2=4

Therefore:A2=18×4A_2=18\times4A2=72A_2=72

Hence:72 cm2\boxed{72\text{ cm}^2}

Worked Example 5: Finding an Unknown Side from Areas

Two similar figures have areas of 25 cm225\text{ cm}^2 and 100 cm2100\text{ cm}^2. A corresponding side of the smaller figure is 6 cm. Find the corresponding side of the larger figure.

Solution

First find the ratio of the areas:10025=4\frac{100}{25}=4

The area ratio is the square of the side ratio:k2=4k^2=4

Therefore:k=2k=2

The corresponding side of the larger figure is:6×2=126\times2=12

Therefore:12 cm\boxed{12\text{ cm}}

Worked Example 6: Similar Triangles

Two similar triangles have corresponding bases of 4 cm and 10 cm. The area of the smaller triangle is 12 cm212\text{ cm}^2. Find the area of the larger triangle.

Solution

Scale factor:k=104=52k=\frac{10}{4}=\frac52

Area factor:k2=(52)2=254k^2=\left(\frac52\right)^2=\frac{25}{4}

Therefore:A2=12×254A_2=12\times\frac{25}{4}A2=3×25A_2=3\times25A2=75A_2=75

Hence:75 cm2\boxed{75\text{ cm}^2}

Worked Example 7: A Real-Life Scale Problem

A small map drawing and a larger similar map have corresponding lengths of 5 cm and 15 cm. The area represented by the smaller drawing is 20 cm220\text{ cm}^2. Find the corresponding area represented by the larger drawing.

Solution

Scale factor:k=155=3k=\frac{15}{5}=3

Area factor:k2=32=9k^2=3^2=9

Therefore:A2=20×9A_2=20\times9A2=180A_2=180

So the corresponding area is:180 cm2\boxed{180\text{ cm}^2}

Area Ratio and Side Ratio of Similar Figures

One of the most important relationships to remember is:Area ratio=(side ratio)2\boxed{\text{Area ratio}=(\text{side ratio})^2}

For example, if the side ratio is:2:32:3

then the area ratio is:22:322^2:3^2=4:9=4:9

Similarly:

Ratio of Corresponding SidesRatio of Areas
1:21:21:41:4
2:32:34:94:9
3:43:49:169:16
3:53:59:259:25
4:54:516:2516:25
2:52:54:254:25

Similar Figures and Scale Factor

The scale factor tells us how much larger or smaller one similar figure is compared with another.

If:k>1k>1

the second figure is an enlargement.

If:0<k<10<k<1

the second figure is a reduction.

For example, if:k=3k=3

the corresponding lengths become three times as large, but the area becomes:32=93^2=9

times as large.

If:k=12k=\frac12

the corresponding lengths become half as large, but the area becomes:(12)2=14\left(\frac12\right)^2=\frac14

of the original area.

Similar Figures vs Congruent Figures

Students sometimes confuse similar and congruent figures.

Similar FiguresCongruent Figures
Same shapeSame shape
Size may be differentSame size
Corresponding sides are proportionalCorresponding sides are equal
Corresponding angles are equalCorresponding angles are equal
Area may be differentArea is equal

Every pair of congruent figures is also similar, because their corresponding side lengths have a ratio of 1.

However, similar figures do not have to be congruent.

Real-Life Applications of Similar Figures

Similar figures are useful in many practical situations.

Maps and Plans

Maps use scale to represent large areas on a smaller surface. Similarity helps relate distances and areas between the drawing and the actual location.

Models

Architectural and engineering models can represent buildings or structures at a smaller scale.

Photography and Images

Changing the size of an image while maintaining its proportions involves the same idea of a scale factor.

Geometry and Construction

Similar shapes can be used to estimate lengths, heights, and areas that are difficult to measure directly.

Technical Drawings

Engineers and designers often use scaled drawings to represent large objects on paper.

Common Mistakes Students Make

1. Using the Scale Factor Directly for Area

A common mistake is to multiply the area by kk instead of k2k^2.

Incorrect:A2=kA1A_2=kA_1

Correct:A2=k2A1\boxed{A_2=k^2A_1}

2. Using Non-Corresponding Sides

The side lengths must correspond to the same positions in the two similar figures.

3. Forgetting to Square a Fraction

If:k=23k=\frac23

then:k2=49k^2=\frac49

not 23\frac23.

4. Confusing Area Ratio with Side Ratio

If the side ratio is:2:52:5

the area ratio is:4:254:25

not 2:52:5.

5. Forgetting Square Units

Area should be expressed using square units, such as:cm2,m2,mm2cm^2,\quad m^2,\quad mm^2

A Quick Method for Exam Questions

When solving an area problem involving similar figures, remember:

Corresponding sides → Scale factor → Square it → Multiply area

For example:Scale factor=new sideold side\text{Scale factor}=\frac{\text{new side}}{\text{old side}}

Then:Area factor=(scale factor)2\text{Area factor}=(\text{scale factor})^2

Finally:New area=Area factor×old area\text{New area}=\text{Area factor}\times\text{old area}

This method works for similar triangles, rectangles, squares, circles, and other similar plane figures.

Frequently Asked Related Questions

How do you find the area of similar figures?

Find the scale factor using corresponding side lengths and then square the scale factor:A2A1=(s2s1)2\boxed{\frac{A_2}{A_1}=\left(\frac{s_2}{s_1}\right)^2}

What is the area of similar figures formula?

The main formula is:A2A1=(s2s1)2\boxed{\frac{A_2}{A_1}=\left(\frac{s_2}{s_1}\right)^2}

or:A2=k2A1\boxed{A_2=k^2A_1}

If the sides of similar figures are doubled, what happens to the area?

If the side lengths are doubled, the area becomes:22=42^2=4

times as large.

If the side ratio is 3:4, what is the area ratio?

The area ratio is:32:42=9:163^2:4^2=9:16

Can similar figures have different areas?

Yes. Similar figures can have different sizes and therefore different areas.

Are all similar figures congruent?

No. Similar figures have the same shape, but their sizes may be different. Congruent figures have both the same shape and the same size.

Short Notes: Area of Similar Figures

Definition

Similar figures have the same shape, corresponding angles equal, and corresponding sides proportional.

Main Formula

A2A1=(s2s1)2\boxed{\frac{A_2}{A_1}=\left(\frac{s_2}{s_1}\right)^2}

Using Scale Factor

If:k=s2s1k=\frac{s_2}{s_1}

then:A2=k2A1\boxed{A_2=k^2A_1}

Important Rule

Area ratio=(side ratio)2\boxed{\text{Area ratio}=(\text{side ratio})^2}

Examples

If side ratio is:2:32:3

area ratio is:4:94:9

If side ratio is:3:53:5

area ratio is:9:259:25

Remember

  • Length changes by kk.
  • Area changes by k2k^2.
  • Always use corresponding sides.
  • Always square the scale factor.
  • Area requires square units.

MCQs: Similar Figures and Their Areas

1. What is true about two similar figures?

A. They always have the same size
B. Their corresponding angles are equal
C. Their areas must be equal
D. Their corresponding sides must be equal

Correct Answer: B

2. If the scale factor between two similar figures is 3, what is the area factor?

A. 3
B. 6
C. 9
D. 12

Correct Answer: C

3. Two similar figures have corresponding sides in the ratio 2:52:5. What is the ratio of their areas?

A. 2:52:5
B. 4:104:10
C. 4:254:25
D. 8:1258:125

Correct Answer: C

4. A similar figure has a scale factor of 4. How many times larger is its area?

A. 4
B. 8
C. 12
D. 16

Correct Answer: D

5. Two similar triangles have corresponding sides 6 cm and 12 cm. What is the scale factor from the smaller triangle to the larger triangle?

A. 1
B. 2
C. 3
D. 6

Correct Answer: B

6. If the area of a smaller similar figure is 10 cm210\text{ cm}^2 and the scale factor is 3, what is the area of the larger figure?

A. 30 cm230\text{ cm}^2
B. 60 cm260\text{ cm}^2
C. 90 cm290\text{ cm}^2
D. 100 cm2100\text{ cm}^2

Correct Answer: C

7. Two similar figures have side ratio 3:43:4. Their area ratio is:

A. 3:43:4
B. 6:86:8
C. 9:169:16
D. 12:1612:16

Correct Answer: C

8. If the corresponding sides of two similar figures are 5 cm and 15 cm, the area factor is:

A. 3
B. 5
C. 9
D. 15

Correct Answer: C

9. The area of a larger similar figure is 80 cm280\text{ cm}^2, and the area of the smaller figure is 20 cm220\text{ cm}^2. What is the scale factor from smaller to larger?

A. 2
B. 3
C. 4
D. 5

Correct Answer: A

10. If the side lengths of a similar figure are reduced by a scale factor of 12\frac12, its area becomes:

A. 12\frac12 of the original
B. 14\frac14 of the original
C. 13\frac13 of the original
D. 2 times the original

Correct Answer: B

11. Which formula gives the relationship between areas of similar figures?

A. A2A1=s2s1\frac{A_2}{A_1}=\frac{s_2}{s_1}
B. A2A1=s2+s1\frac{A_2}{A_1}=s_2+s_1
C. A2A1=(s2s1)2\frac{A_2}{A_1}=\left(\frac{s_2}{s_1}\right)^2
D. A2=A1+s2A_2=A_1+s_2

Correct Answer: C

12. Two similar rectangles have corresponding sides in the ratio 1:31:3. Their areas are in the ratio:

A. 1:31:3
B. 1:61:6
C. 1:91:9
D. 3:93:9

Correct Answer: C

Worksheet / Assignment: Area of Similar Figures

Part A: Definitions and Concepts

1. Define similar figures.

2. State two properties of similar figures.

3. What is meant by corresponding sides?

4. What is a scale factor?

5. State the formula for the ratio of the areas of two similar figures.

Part B: Formula-Based Questions

6. Two similar figures have corresponding sides in the ratio 2:32:3. Find the ratio of their areas.

7. Two similar triangles have corresponding sides of 5 cm and 15 cm. Find the scale factor and area factor.

8. The scale factor between two similar figures is 4. By what factor does the area change?

Part C: Numerical Problems

9. Two similar triangles have corresponding sides of 6 cm and 12 cm. The area of the smaller triangle is 18 cm218\text{ cm}^2. Find the area of the larger triangle.

10. Two similar rectangles have corresponding lengths of 8 cm and 12 cm. If the area of the smaller rectangle is 24 cm224\text{ cm}^2, find the area of the larger rectangle.

11. Two similar figures have corresponding sides of 9 cm and 15 cm. The area of the smaller figure is 27 cm227\text{ cm}^2. Find the area of the larger figure.

12. Two similar figures have areas of 36 cm236\text{ cm}^2 and 81 cm281\text{ cm}^2. If a corresponding side of the smaller figure is 8 cm, find the corresponding side of the larger figure.

Part D: Word Problems

13. A model of a rectangular garden is similar to the actual garden. A corresponding length on the model is 4 m, while the corresponding length of the actual garden is 12 m. If the area represented by the model is 15 m215\text{ m}^2, find the corresponding actual area.

14. A photograph is enlarged so that every length is multiplied by 2.5. By what factor does its area increase?

15. Two similar triangular plots of land have corresponding side lengths in the ratio 3:73:7. If the area of the smaller plot is 27 m227\text{ m}^2, find the area of the larger plot.

Answer Key

1. Figures having the same shape, with equal corresponding angles and proportional corresponding sides.

2. Any two valid properties, such as equal corresponding angles and proportional corresponding sides.

3. Sides that occupy matching positions in two similar figures.

4. The ratio between corresponding lengths of two similar figures.

5.A2A1=(s2s1)2\frac{A_2}{A_1}=\left(\frac{s_2}{s_1}\right)^2

6.22:32=4:92^2:3^2=4:9

7.k=155=3k=\frac{15}{5}=3

Area factor:32=93^2=9

8.42=164^2=16

The area changes by a factor of 16.

9.k=126=2k=\frac{12}{6}=2A2=18(22)=18(4)=72A_2=18(2^2)=18(4)=72

Answer: 72 cm272\text{ cm}^2

10.k=128=32k=\frac{12}{8}=\frac32A2=24(32)2A_2=24\left(\frac32\right)^2=24(94)=54=24\left(\frac94\right)=54

Answer: 54 cm254\text{ cm}^2

11.k=159=53k=\frac{15}{9}=\frac53A2=27(53)2A_2=27\left(\frac53\right)^2=27(259)=75=27\left(\frac{25}{9}\right)=75

Answer: 75 cm275\text{ cm}^2

12.8136=94\frac{81}{36}=\frac94

Therefore:k=32k=\frac32

Corresponding larger side:8×32=128\times\frac32=12

Answer: 12 cm

13.k=124=3k=\frac{12}{4}=3A2=15(32)=15(9)=135A_2=15(3^2)=15(9)=135

Answer: 135 m2135\text{ m}^2

14.2.52=6.252.5^2=6.25

Answer: The area increases by a factor of 6.25.

15.73\frac{7}{3}

Area factor:(73)2=499\left(\frac73\right)^2=\frac{49}{9}

Therefore:27×499=3×49=14727\times\frac{49}{9}=3\times49=147

Answer: 147 m2147\text{ m}^2

FAQs About Similar Figures

1. What are similar figures?

Similar figures are figures with the same shape. Their corresponding angles are equal and their corresponding side lengths are proportional.

2. What is the formula for the area of similar figures?

The formula is:A2A1=(s2s1)2\boxed{\frac{A_2}{A_1}=\left(\frac{s_2}{s_1}\right)^2}

3. Why do we square the scale factor for area?

Area is two-dimensional. When every length is multiplied by kk, both dimensions are multiplied by kk, giving an area factor of k×k=k2k\times k=k^2.

4. If the side length is doubled, does the area double?

No. If the side length is doubled, the area becomes four times as large:22=42^2=4

5. Can two similar figures have different areas?

Yes. Similar figures can have different sizes, so their areas can also be different.

6. What is the difference between similar and congruent figures?

Similar figures have the same shape but may have different sizes. Congruent figures have the same shape and the same size.

7. How do I solve an area-of-similar-figures question?

Identify corresponding sides, calculate the scale factor, square the scale factor, and use it to calculate the unknown area.

8. Where can I find more mathematics notes and practice resources?

Students can find mathematics notes, recorded lectures, assessments, worksheets, lesson plans, and solved questions at Nisar Math Academy. Some resources are available free, while additional courses and resources are provided through membership.

Conclusion

The area of similar figures can be found easily once the relationship between side lengths, scale factor, and area is understood.

The most important rule is:Area ratio=(side ratio)2\boxed{\text{Area ratio}=(\text{side ratio})^2}

If the scale factor is kk, then:A2=k2A1\boxed{A_2=k^2A_1}

Remember that lengths change by the scale factor, while areas change by the square of the scale factor. Always identify corresponding sides carefully and give the final area in square units.

For students looking for additional online math academy notes, recorded mathematics lectures, assessments, worksheets, and other learning resources, Nisar Math Academy provides a range of resources designed to support mathematics learning.

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