Understanding the angle of elevation and angle of depression is an important part of trigonometry. These angles are commonly used to solve problems involving the height and distance of objects such as buildings, towers, trees, mountains, and airplanes.
In this article, we will learn the angle of elevation and depression definition, their differences, formulas, examples, and how to solve angle of elevation and depression questions step by step.
The angle of elevation is the angle formed between the horizontal line through the observer’s eye and the line of sight when the observer looks upward at an object.
If an object is above the horizontal level of an observer, the angle made by the line of sight with the horizontal line is called the angle of elevation.
In simple words:
When we look upward at an object, the angle between our horizontal line and our line of sight is called the angle of elevation.
For example, suppose a student is standing on the ground and looking at the top of a building. The angle between the horizontal line from the student’s eye and the line joining the student’s eye to the top of the building is the angle of elevation.
The angle of depression is the angle formed between the horizontal line through the observer’s eye and the line of sight when the observer looks downward at an object.
If an object is below the horizontal level of an observer, the angle made by the line of sight with the horizontal line is called the angle of depression.
In simple words:
When we look downward at an object, the angle between our horizontal line and our line of sight is called the angle of depression.
For example, a person standing on the roof of a building and looking down at a car on the road observes the car at an angle of depression.
The main difference can be understood easily:
Both angles are measured from a horizontal line.
| Angle of Elevation | Angle of Depression |
|---|---|
| The object is above the observer. | The object is below the observer. |
| The observer looks upward. | The observer looks downward. |
| The angle is measured upward from the horizontal. | The angle is measured downward from the horizontal. |
| It is commonly used to find the height of an object. | It is commonly used to find the distance or height of an object below the observer. |
To solve problems involving the angle of elevation and depression, we should understand the following terms.
The person or point from which an object is being viewed is called the observer.
The straight line joining the observer’s eye to the object being observed is called the line of sight.
A line parallel to the ground passing through the observer’s eye is called the horizontal line.
A line perpendicular to the horizontal line is called a vertical line.
The angle between the horizontal line and the line of sight when the object is above the observer.
The angle between the horizontal line and the line of sight when the object is below the observer.
Angles of elevation and depression have many practical applications. They can be used to calculate:
These problems are usually solved by forming a right-angled triangle and applying trigonometric ratios.
Most angle of elevation problems involve a right triangle. Depending on the information given, we can use sine, cosine, or tangent.
For example, if:
then tangent is usually the most convenient ratio.
tan θ = Opposite / Adjacent
Therefore:
Height = Distance × tan θ
and
Distance = Height / tan θ
Here, θ represents the angle of elevation.
Angle of depression problems are also solved using trigonometric ratios.
If the vertical height and horizontal distance form the opposite and adjacent sides of a right triangle, respectively, then:
tan θ = Height / Horizontal Distance
Therefore:
Height = Horizontal Distance × tan θ
and
Horizontal Distance = Height / tan θ
The appropriate trigonometric ratio should always be selected according to the sides that are known and unknown.
A very important concept is that an angle of elevation and an angle of depression can be equal when they are formed by two parallel horizontal lines and the same line of sight.
For example, suppose an observer is standing on the top of a building and looking down at a person on the ground. The angle of depression at the observer and the corresponding angle of elevation at the person are equal because the horizontal lines are parallel.
Thus:
Angle of depression = Corresponding angle of elevation
This relationship is often used to solve trigonometric problems.
Follow these steps:
Draw a simple diagram showing the observer, object, horizontal line, vertical height, and line of sight.
Most problems involving these angles can be represented by a right-angled triangle.
Write down the given height, distance, or angle.
Determine whether you need to find the height, horizontal distance, or angle.
Use:
sin θ = Opposite / Hypotenuse
cos θ = Adjacent / Hypotenuse
tan θ = Opposite / Adjacent
Put the known values into the selected formula.
Solve the equation and write the answer with the correct unit.
A student stands 20 m away from a tower. The angle of elevation of the top of the tower is 30°. Find the height of the tower.
Given:
Horizontal distance = 20 m
Angle of elevation = 30°
Let the height of the tower be h.
Using tangent:
tan 30° = h / 20
Since:
tan 30° = 1/√3
Therefore:
1/√3 = h/20
So:
h = 20/√3
Rationalizing:
h = 20√3/3 m
Therefore, the height of the tower is approximately:
11.55 m
A tower is 15 m high. The angle of elevation of its top from a point on the ground is 45°. Find the distance of the point from the foot of the tower.
Given:
Height = 15 m
Angle of elevation = 45°
Let the horizontal distance be d.
Using tangent:
tan 45° = 15/d
Since:
tan 45° = 1
Therefore:
1 = 15/d
So:
d = 15 m
Therefore, the required distance is 15 m.
A person standing on the top of a 20 m high building observes a car on the road. The angle of depression is 45°. Find the horizontal distance of the car from the building.
Given:
Height = 20 m
Angle of depression = 45°
The corresponding angle of elevation from the car is also 45°.
Let the horizontal distance be d.
Using tangent:
tan 45° = 20/d
Since:
tan 45° = 1
Therefore:
1 = 20/d
So:
d = 20 m
Therefore, the car is 20 m from the foot of the building.
The angle between the horizontal line and the line of sight when the observer looks upward at an object is called the angle of elevation.
The angle between the horizontal line and the line of sight when the observer looks downward at an object is called the angle of depression.
The straight line joining the observer’s eye and the object is called the line of sight.
For a right triangle:
tan θ = Opposite / Adjacent
Therefore:
Height = Distance × tan θ
Elevation → Looking upward
Depression → Looking downward
When the horizontal lines are parallel:
Angle of elevation = Corresponding angle of depression
The angle formed between the horizontal line and the line of sight when an observer looks upward is called:
A. Angle of depression
B. Angle of elevation
C. Right angle
D. Reflex angle
Answer: B. Angle of elevation
When an observer looks downward at an object, the angle formed is called:
A. Angle of elevation
B. Angle of depression
C. Acute angle only
D. Straight angle
Answer: B. Angle of depression
The straight line joining the observer’s eye to the object is called:
A. Horizontal line
B. Vertical line
C. Line of sight
D. Base line
Answer: C. Line of sight
Which trigonometric ratio is commonly used when the opposite and adjacent sides are known?
A. Sine
B. Cosine
C. Tangent
D. Secant
Answer: C. Tangent
The angle of elevation is measured from the:
A. Vertical line
B. Horizontal line
C. Base only
D. Hypotenuse
Answer: B. Horizontal line
If the angle of elevation of the top of a tower is 45° and the horizontal distance is 10 m, the height of the tower is:
A. 5 m
B. 10 m
C. 20 m
D. 45 m
Answer: B. 10 m
If the angle of depression is 30°, the corresponding angle of elevation is:
A. 15°
B. 30°
C. 60°
D. 90°
Answer: B. 30°
An observer looking at an airplane above him is observing it at an:
A. Angle of depression
B. Angle of elevation
C. Obtuse angle
D. Straight angle
Answer: B. Angle of elevation
An observer standing on a building looks at a car on the road below. The angle observed is:
A. Angle of elevation
B. Angle of depression
C. Right angle
D. Reflex angle
Answer: B. Angle of depression
In a right triangle:
A. tan θ = Adjacent/Opposite
B. tan θ = Hypotenuse/Opposite
C. tan θ = Opposite/Adjacent
D. tan θ = Opposite/Hypotenuse
Answer: C. tan θ = Opposite/Adjacent
The angle of elevation and depression are important applications of trigonometry. The angle of elevation is used when an observer looks upward, while the angle of depression is used when an observer looks downward.
By drawing a suitable right-angled triangle and applying trigonometric ratios such as sine, cosine, and tangent, we can solve many real-life problems involving heights and distances.
Students should practise different angle of elevation and depression questions because these concepts are frequently used in trigonometry and mathematical problem-solving.
For more mathematics notes, recorded lectures, assessments, lesson plans, and other educational resources, visit Nisar Math Academy. Students can access selected free Class 9 Maths resources, while full-course content is available through website membership.
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